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8 June, 08:18

Earl paid $37.95 for admission to the amusement park. Each ride costs and additional $4.25. Earl only has $75. What is the maximum number of rides he can go on?

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Answers (2)
  1. 8 June, 08:32
    0
    8

    Step-by-step explanation:

    1. Determine how much Earl has to spend on rides. Subtract the admission (37.95) from his starting number (75)

    75.00-37.95 = 36.05

    2. Divide 36.05 by the cost per ride (4.25)

    36.05/4.25 = 8.48

    Since Earl cannot ride part of a ride (.48) he can only ride 8 rides.
  2. 8 June, 08:35
    0
    8 rides is the maximum

    Step-by-step explanation:

    The equation is 37.95+x (4.25) ≥75

    x is the number of rides

    Start by taking away the admission cost from the total amount he has

    75-37.95=37.05

    Now we know each ride costs 4.25 extra

    so divide 37.05 by 4.25

    you get 8.7176 ...

    the whole number in there is 8

    he can go on a maximum of 8 rides.

    check your answer by plugging the numbers into the equation

    37.95+8 (4.25) ≥75

    37.95+34≥75

    71.95≥75

    Just to make sure he can't go on any more rides subtract 71.95 from 75

    75-71.95=3.05

    no he cannot go on anymore rides
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