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7 August, 16:58

Solve the triangle. A = 50°, b = 13, c = 6

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  1. 7 August, 17:19
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    Hello,

    a²=b²+c²-2bc*cos A

    ==>a²=13²+6²-2*13*6*cos 50°=104.7251 ...

    ==>a=10.2335 ...

    sin C/c=sin A/a

    ==>sin C=qin 50°-6/10.2335 ... = 0.449137 ...

    ==>angle C=26.688394 ... °

    angle B==180°-50°-26.688394 ... °=103.311610 ... °
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