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Eden Medina
Mathematics
7 August, 16:58
Solve the triangle. A = 50°, b = 13, c = 6
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Trixie
7 August, 17:19
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Hello,
a²=b²+c²-2bc*cos A
==>a²=13²+6²-2*13*6*cos 50°=104.7251 ...
==>a=10.2335 ...
sin C/c=sin A/a
==>sin C=qin 50°-6/10.2335 ... = 0.449137 ...
==>angle C=26.688394 ... °
angle B==180°-50°-26.688394 ... °=103.311610 ... °
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