In a group of ten students, eight own an Android smartphone. If you select two students from this group at random without replacement, what is the probability, rounded to 3 decimal places, that both own an Android?

P = 0.622

Step-by-step explanation:

Since 8/10 own an Android, the probability on the first selection is 8/10.

Since the second selection is done without replacement (meaning the first selection is removed from the available choices) the probability of getting a student who owns an Android is 7/9 (we lose one possible Andriod, and one total person from the selection pool).

To solve this we multiply the probabilities together ...

(8/10) (7/9) = 56/90 which equals 0.622222 as a decimal, but the question wants it rounded to 3 decimals, so the final answer is 0.622