Joanne bought 3 baseball cards for $160. If the first card was as expensive as the combined price of the second and the third cards, and the second card cost $20 more than the third card, what is the price of the first card?

Let b represent the third card

let (b+20) represent the second card

let (2b+20) represent the first card

(2b+20) + (b+20) + b=160

4b+40=160

4b=160-40

4b=120

4b/4=120/4

b=30

2b+20

= 2 (30) + 20

= 60+20

= 80

b+20

= 30=20

= 60

Therefore, the first card was $80, the second card was $50 and the third card was $30.