F (1) = 1

f (2) = 2

f (n) = f (n - 2) + f (n - 1)

f (3) = ?

Question

Felicity Kane

Mathematics

30 May, 18:40

F (1) = 1

f (2) = 2

f (n) = f (n - 2) + f (n - 1)

f (3) = ?

+5

Answers (1)

Know the Answer?

Kymani Valentine · Answer 1

3

Step-by-step explanation:

To find f (3) we just need to plug in 3 wherever we see an n

f (3) = f (3 - 2) + f (3 - 1)

f (3) = f (1) + f (2)

Since f (1) and f (2) are given, we can plug in the respective values

f (3) = f (1) + f (2) → f (3) = 1 + 2 = 3

F (1) = 1f (2) = 2f (n) = f (n - 2) + f (n - 1)f (3) = ?

F (1) = 1

f (2) = 2

f (n) = f (n - 2) + f (n - 1)

f (3) = ?