The perimeter of a college athletic field is 96 meters and the length is 12m more than the width. Find the width and length?

We are asked to define the width and length of a rectangular college athletic field with a parameter of 98 and length 12 more than the width, we represent x as the width, that is the length is x+12. Using parameter formula: 96/2 = x + x + 12; 48 = 2x + 12; x is equal to 18 m while x + 12 is equal to 30 m