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For the following data values below, construct a 98% confidence interval if the sample mean is known to be 9.808 and the population standard deviation is 5.013. (Round to the nearest thousandth) (Type your answer in using parentheses! Use a comma when inputing your answers! Do not type any unnecessary spaces! List your answers in ascending order!) for example: (0.45,0.78)

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  1. 8 June, 23:06
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    (-19.92, 21.488)

    Step-by-step explanation:

    given dа ta:

    98% confidence interval

    Critical value of z at 98% confidence interval is t = 2.33

    standard deviation = 5.031

    sample mean = 9.808

    z statistic to construct 98% confidence interval.

    Margin of error = t * standard deviation = 2.33 * 5.013 = 11.680

    98% confidence interval of mean is,

    (9.808 - 11.68, 9.808 + 11.68)

    (-19.92, 21.488)
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