Liam had a number of chocolates in his pocket. he decided to give most of them away before they melted. so he gave two-thirds to Lucy, then one-fifth of the remainder to his mother, which left twelve for himself. what was the original amount of chocolates?

Question

Pooch

Mathematics

26 August, 01:16

Liam had a number of chocolates in his pocket. he decided to give most of them away before they melted. so he gave two-thirds to Lucy, then one-fifth of the remainder to his mother, which left twelve for himself. what was the original amount of chocolates?

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Answers (1)

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Sharon Delgado · Answer 1

Let x be the original number of chocolates:-

x - (2/3) x - (1/5) (x - (2/3) x) = 12

x - (2/3) x - (1/5) x + (2/15) x = 12

15x - 10x - 3x + 2x = 180

4x = 180

x = 45

original amount of chocolates = 45