Find (g o f) (x), given:

f (x) = x+1 and g (x) = x2 - x.

(g o f) (x) is the same as g (f (x))

f (x) = x+1 g (x) = x² - x

g (f (x)) = g (x+1)

Note g (x) = x² - x, therefore g (x+1) would be that anywhere we see x in g (x) we replace it with (x+1)

g (x) = x² - x

g (x+1) = (x+1) ² - (x+1) = x² + 2x + 1 - x - 1 = x² + 2x-x + 1 - 1 = x² + x

Therefore (g o f) (x) = x² + x