Match the following. 1. the domain set of C = { (2, 5), (2, 6), (2, 7) } {3, 4, 5, 6} 2. the range set of E = { (3, 3), (4, 4), (5, 5), (6, 6) } domain = {all real numbers}: range = {y: y = 3} 3. the range and domain of F = x + y = 10 {2} 4. the range and domain of P = y = 3 domain = range = {all real numbers}

the domain set of C = { (2, 5), (2, 6), (2, 7) } = {2}

the range set of E = { (3, 3), (4, 4), (5, 5), (6, 6) } = {3, 4, 5, 6}

the range and domain of F = (x, y) = domain = range = {all real numbers}

the range and domain of P = y = 3 = domain = {all real numbers}: range = {y: y = 3}

1. The domain set of C = { (2,5), (2,6), (2,7) } is the set of all first elements of the ordered pairs.

Therefore, domain set of C = {2}

2. The range set of E = { (3, 3), (4, 4), (5, 5), (6, 6) } is the set of all second elements of the ordered pairs.

Therefore, range set of E = {3,4,5,6}

3. We need to find the range and domain of F = x + y = 10.

Clearly, the domain is the set of all real numbers.

Also, if x is a real number, then 10 - x is also a real number.

We have, x + y = 10

y = 10 - x

So, y is also a real number.

Therefore, range and domain of F = {all real numbers}

4. We need to find the range and domain of P = y = 3.

Clearly, the domain is the set of all real numbers.

Since, the y = 3 (the second element of the ordered pair), the range is the singleton set {2}.

Hence, domain = {all real numbers} and range = {y : y = 3}