Find the fifth term of the sequence if a15=29 and a21=47

Question

Franco Cole

Mathematics

19 August, 11:35

Find the fifth term of the sequence if a15=29 and a21=47

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Answers (1)

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Talan Riggs · Answer 1

We have a15 = a1 + 14 x r and a21 = a1 + 20 x r 29 = a1 + 14 x r and 47 = a1 + 20 x r;

Then, 47 - 29 = (20 x r + a1) - (14 x r + a1);

18 = 6 x r;

r = 3;

We have 29 = a1 + 42;

a1 = 29 - 42;

a1 = - 13;

Finally, a5 = a1 + 4 x r = - 13 + 4 x 3 = - 13 + 12 = - 1.