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30 July, 21:01

What is the root of the equation 6x^2-7x-5=0

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  1. 30 July, 21:06
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    The roots are {-1/2, 5/3}.

    Step-by-step explanation:

    6x^2 - 7x - 5 = 0

    Use the 'ac' method:

    6 * - 5 = - 30 so we need to find 2 values whose product is - 30 and whose sum = the coefficient of x in the given equation (-7).

    -10 and + 3 fit the bill so we write:

    6x^2 - 7x - 5 = 0

    6x^2 + 3x - 10x - 5 = 0 Factor by grouping:

    3x (2x + 1) - 5 (2x + 1) = 0

    (3x - 5) (2x + 1) = 0

    So 3x - 5 = 0 gives x = 5/3, and

    2x + 1 = 0 gives x = - 1/2.
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