Given: ΔPSQ, PS = SQ PΔPSQ = 50 SQ - PQ = 1 Find: Area of ΔPSQ

The first part is to find the length SQ which is equal to SP.

Use the sine rule.

SQ/sin 65 = (SQ - 1) / Sin50

(sin50) / (sin 65) = (SQ-1) / SQ

0.8452 (SQ) = SQ-1

0.1547SQ = 1

SQ = 6.46

The formula to apply here is:

Area=1/2 (SQ) (SQ) sin50

= 0.5 * 6.46 * 6.46 * sin50

= 15.984