A rubber ball is dropped from a height of 128 feet. After each bounce, it rebounds one fourth of the distance it fell. How far does the ball fall on its third fall?

first fall 128 feet,

second fall ¼•128=32 feet,

third fall ¼•32=8 feet

8ft

Step-by-step explanation:

The drop is 128 ft

The first bounce is 1/4 the drop (2nd fall)

1/4 (128) = 32 ft

The second bounce is 1/4 of the first bounce (This would be considered the third fall)

1/4 (32) = 8 ft