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8 January, 05:54

Use a truth table to show that P Qand (~PV Q) A (~QV P) are equivalen

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  1. 8 January, 06:03
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    Answer: The given logical equivalence is proved below.

    Step-by-step explanation: We are given to use truth tables to show the following logical equivalence:

    P ⇔ Q ≡ (∼P ∨ Q) ∧ (∼Q ∨ P)

    We know that

    two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

    The truth table is as follows:

    P Q ∼P ∼Q P⇔ Q ∼P ∨ Q ∼Q ∨ P (∼P ∨ Q) ∧ (∼Q ∨ P)

    T T F F T T T T

    T F F T F F T F

    F T T F F T F F

    F F T T T T T T

    Since the corresponding truth vales for P ⇔ Q and (∼P ∨ Q) ∧ (∼Q ∨ P) are same, so the given propositions are logically equivalent.

    Thus, P ⇔ Q ≡ (∼P ∨ Q) ∧ (∼Q ∨ P).
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