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26 October, 01:24

A new surgery is successful 85% of the time. If the results of 6 such surgeries are randomly sampled, what is the probability that fewer than 4 of them are successful

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  1. 26 October, 01:45
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    The probability that fewer than 4 of them are successful are 0.9527

    Explanation:

    Given:

    number of trials, n = 6

    p (successful) = 0.85

    P (x > = 4) = ?

    The problem can be solved using binomial probability formula.

    P (x > = 4) = 1 - binomcdf (6,0.85,4) = 1 - 0.0473

    = 0.9527

    Therefore, the probability that fewer than 4 of them are successful are 0.9527
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