Given the function f (x) = x^2-7 and g (x) = 2x-x^3 what is the value of f (g (2))

9

Step-by-step explanation:

First lets find g (2) because thats inside the f equation.

g (x) = 2x-x^3

g (2) = 2 (2) - (2) ^3

g (2) = 4 - 8

g (2) = - 4

So now we are finding

f (g (2)) = > f (-4)

f (x) = x^2 - 7

f (-4) = (-4) ^2 - 7

Remember, because the square is outside the parentheses due to us plugging in a value, it becomes positive

f (-4) = 16 - 7

f (-4) = 9