Find two consecutive integers such that twice the first added to three times the second is equal to 83

Let the first number=x and the second number = x+1 so

2 (x) + 3 (x+1) = 83 2 (16) + 3 (17) = 83

2x+3x+3=83 32+51=83

5x=83-3

5x=80

5x/5=80/5

x=16 16+1=17

Therefor the two consecutive integers are 16 and 17

First number - a second number - a + 2 a + a + 2 = 83 2a = 81 40.5 = 41 first number - 41 second number - 43