How many ways can 5 people-A, B, C, D, and E-sit in a row at a movie theater if (a) A

and B must sit together; (b) C must sit to the right of, but not necessarily next to, B; (C) D

and E will not sit next to each other?

Question

Alana Beltran

Mathematics

25 October, 11:13

How many ways can 5 people-A, B, C, D, and E-sit in a row at a movie theater if (a) A

and B must sit together; (b) C must sit to the right of, but not necessarily next to, B; (C) D

and E will not sit next to each other?

+1

Answers (1)

Know the Answer?

Kaliyah Oneal · Answer 1

EABDC?

Explanation:

I don't know who C must sit to the right of I was assuming A but not sure.

If A and B must sit next to each other and D and E cannot split D and E on either side of A and B. C doesn't have to sit directly next to B but to the right of A so sit it next to D

How many ways can 5 people-A, B, C, D, and E-sit in a row at a movie theater if (a) Aand B must sit together; (b) C must sit to the right of, but not necessarily next to, B; (C) Dand E will not sit next to each other?

How many ways can 5 people-A, B, C, D, and E-sit in a row at a movie theater if (a) A

and B must sit together; (b) C must sit to the right of, but not necessarily next to, B; (C) D

and E will not sit next to each other?