Ask Question
12 July, 22:17

In a box of 15 tablets, 4 of the tablets are defective. Three tablets are selected at random. what is the probability that a store buys three tablets and receives: a) no defective tablets, b) one defective tablet, and c) at least one non-defective tablet.

+3
Answers (1)
  1. 12 July, 22:33
    0
    a) 0.394

    b) 0.430

    c) 0.981

    Step-by-step explanation:

    Use binomial probability:

    P = nCr pʳ (1-p) ⁿ⁻ʳ

    where n is the number of trials,

    r is the number of successes,

    and p is the probability of success.

    Here, n = 3 and p = 4/15.

    r is the number of defective tablets.

    a) If r = 0:

    P = ₃C₀ (4/15) ⁰ (1-4/15) ³⁻⁰

    P = 1 (1) (11/15) ³

    P = 0.394

    b) If r = 1:

    P = ₃C₁ (4/15) ¹ (1-4/15) ³⁻¹

    P = 3 (4/15) (11/15) ²

    P = 0.430

    c) If r ≠ 3:

    P = 1 - ₃C₃ (4/15) ³ (1-4/15) ³⁻³

    P = 1 - 1 (4/15) ³ (1)

    P = 0.981
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “In a box of 15 tablets, 4 of the tablets are defective. Three tablets are selected at random. what is the probability that a store buys ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers