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Jones
Mathematics
18 September, 20:35
X^4/3-7x^2/3+10=0 what is x
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Stephen Hamilton
18 September, 20:57
0
Take the root of both sides and solve.
x = the square root of 7 (X^4=30) over 7
Subtract the square root of 7 (X^4+30) over 7
Not sure if this is correct ...
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Serenity Carlson
18 September, 21:04
0
Solve for x:10 - (7 x^2) / 3 + X^4/3 = 0
Subtract X^4/3 + 10 from both sides: - (7 x^2) / 3 = - X^4/3 - 10
Multiply both sides by - 3/7:x^2 = X^4/7 + 30/7
Take the square root of both sides:Answer: x = sqrt (X^4/7 + 30/7) or x = - sqrt (X^4/7 + 30/7)
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