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21 June, 06:31

If 0 < z ≤ 90 and sin (9z - 1) = cos (6z + 1), what is the value of z?

z = 3

z = 4

z = 5

z = 6

+2
Answers (1)
  1. 21 June, 06:50
    0
    The value of z is:

    z = 6

    Step-by-step explanation:

    We have been given 4 options of z. Lets substitute each value in the given equation to see which option satisfies.

    For z = 3

    sin (9z - 1) = cos (6z + 1)

    sin (9 (3) - 1) = cos (6 (3) + 1)

    sin (26) = cos (19)

    0.438 = 0.945

    FALSE

    For z = 4

    sin (9z - 1) = cos (6z + 1)

    sin (9 (4) - 1) = cos (6 (4) + 1)

    sin (35) = cos (25)

    0.574 = 0.965

    FALSE

    For z = 5

    sin (9z - 1) = cos (6z + 1)

    sin (9 (5) - 1) = cos (6 (5) + 1)

    sin (44) = cos (31)

    0.695 = 0.857

    FALSE

    For z = 6

    sin (9z - 1) = cos (6z + 1)

    sin (9 (6) - 1) = cos (6 (6) + 1)

    sin (53) = cos (37)

    0.799 = 0.799

    TRUE
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