Find the first 4 terms of this equation, f (n) = f (n-1) + 5 f (1) = - 2

The first fourth term of the equation are "3, 8, 13 and 18".

Step-by-step explanation:

We have,

f (n) = f (n - 1) + 5

and f (1) = - 2 ... (1)

To find, the first four terms of the given equation = ?

Put n = 2, 3, 4, 5, ...

Put n = 2, we get

f (2) = f (2 - 1) + 5 = f (1) + 5

Using (1), we get

f (2) = - 2 + 5 = 3 ... (2)

Put n = 3, we get

f (3) = f (3 - 1) + 5 = f (2) + 5

Using (2), we get

f (3) = 3 + 5 = 8 ... (3)

Put n = 4, we get

f (4) = f (4 - 1) + 5 = f (3) + 5

Using (3), we get

f (4) = 8 + 5 = 13 ... (4)

Put n = 5, we get

f (5) = f (5 - 1) + 5 = f (4) + 5

Using (4), we get

f (5) = 13 + 5 = 18

Thus, the first fourth term of the equation are 3, 8, 13 and 18.