Consider ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD. Can it be concluded that ΔWXY ≅ ΔBCD by SAS? Why or why not? no, because the third corresponding sides must also be given as congruent no, because the corresponding congruent angles listed are not the included angles no, because all corresponding angles must be given as congruent yes, because two corresponding sides and a corresponding angle are congruent

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Lin

Mathematics

11 November, 19:28

Consider ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD. Can it be concluded that ΔWXY ≅ ΔBCD by SAS? Why or why not? no, because the third corresponding sides must also be given as congruent no, because the corresponding congruent angles listed are not the included angles no, because all corresponding angles must be given as congruent yes, because two corresponding sides and a corresponding angle are congruent

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Scarlett Winters · Answer 1

no, because the corresponding congruent angles listed are not the included angles

Step-by-step explanation:

Sides WX and WY meet at vertex W. Corresponding sides BC and BD meet at vertex B. Thus, for SAS, the angles that need to be congruent are the included angles W and B, not X and C.