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12 June, 15:42

18x^=12+15x How to solve

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  1. 12 June, 15:59
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    I'm assuming the 18x is to the power of 2. To solve this you first rearrange it to 18x^2 - 15x-12 = 0

    You can begin to factorize it by finding two numbers which add up to - 15 and multiply to - 216. These two numbers would be - 24 and 9.

    You can now write the equation as 18x^2 - 24x + 9x - 12 = 0

    then, 6x (3x-4) + 3 (3x-4)

    = (6x+3) (3x-4) = 0

    Then to find what x is either (6x-3) = 0 or (3x-4) = 0

    Therefore 6x-3=0

    6x=3

    x=2

    and when 3x-4=0

    3x=4

    x=4/3

    Final Answers: x = 2 or 4/3
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