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12 August, 22:14

Given log4^3 = 0.792 and log4^ 21=2.196 what is log4^7

1.404

1.739

2.773

2.988

+5
Answers (1)
  1. 12 August, 22:33
    0
    We have to find log4^7 if we know that log4^3 = 0.792 and log4^21 = 2.196.

    We already know that:

    log (x/y) = log x - log y

    log4^21 = log4^ (21 / 3) =

    = log4^ 21 - log4^ 7 = 2.196 - 0.797 = 1.404

    Answer:

    A) 1.404
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