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27 March, 22:43

The heat loss h (in watts) through a single-pane glass window varies jointly with the window's area A (in square meters) and the difference between the inside and outside temperatures d (in kelvins). Write an equation relating h, A, d, and a constant k. If a single-pane of glass with an area of 1.00 square meter and a temperature difference of 1.00 kelvin has a heat loss of 5.70 watts, then what is the heat loss through a single-pane window with an area of 2.50 square meters and a temperature difference of 20 kelvins?

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  1. 27 March, 22:47
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    Answer: 285 watts

    Step-by-step explanation:

    The heat loss h (in watts) through a single-pane glass window varies jointly with the window's area A (in square meters) and the difference between the inside and outside temperatures d (in kelvins). The equation relating h, A, d, and a constant k would be

    h = kAd

    If a single-pane of glass with an area of 1.00 square meter and a temperature difference of 1.00 kelvin has a heat loss of 5.70 watts, it means that

    5.7 = k * 1 * 1

    k = 5.7/1 = 5.7

    The equation becomes

    h = 5.7Ad

    Therefore, the heat loss through a single-pane window with an area of 2.50 square meters and a temperature difference of 20 kelvins would be

    h = 5.7 * 2.5 * 20

    h = 285 watts
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