On the surface of the moon, the value of g is 1.67 m/s2. What is the horizontal distance traveled during a 2.00-meter high jump if the jumper runs as at 20 miles per hour?

Question

Nathalie Warner

Mathematics

2 February, 11:15

On the surface of the moon, the value of g is 1.67 m/s2. What is the horizontal distance traveled during a 2.00-meter high jump if the jumper runs as at 20 miles per hour?

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Marcelo Booth · Answer 1

To solve this question, you need to find how long jump is. For 2m high with 1.67 m/s2 it would be:

h = 1/2 gt^2

2 = 1/2 * (1.67) t^2

t^2 = 1.67

t = 1.29

If the speed is 20 mph and the jump is 2 second, the distance traveled would be:

20 miles / hour * 1.29 second * (1 hour/3600second) = 0.007179 miles

If you need to convert it to meter then: 0.007179 mile * 1609.34meter / mile = 11.55 meter