What are the coordinates of the hole in the graph of the function f (x)

F (x) = x^2 + 3x - 28 / X + 7

(-7, 0) are the coordinates of the function.

Step-by-step explanation:

The given function is f (x) = (x²+3x-28) / (x+7).

We have to find the coordinates of hole of the given function.

To find the coordinates of the hole we will find the factors of the numerator first.

x² + 3x - 28 = x² + 7x - 4x - 28

= x (x + 7) - 4 (x + 7)

= (x + 7) (x - 4)

Now we know that factor (x + 7) is common as denominator therefore these factors will get cancelled.

Therefore x + 7 = 0

Or x = - 7

and for x = - 7 the value of y = (x²+3x-28) / (x+7) = 0

Therefore the coordinates of the hole of the given function is (-7, 0).

The coordinates are (-7, - 11) actually. I took the test already.

Good luck!