Brent's after-school game club has 12 members from which a six-member team is created. Miguel's after-school sports club has 10 members from which a six-member team is created.

Which student's club has more possible combinations for his six-member team?

Brent's club has more possible team combinations because he has fewer members on each team than Miguel's does.

Brent's club has more possible team combinations because there are more members to choose from.

Miguel's club has more possible team combinations because there are fewer members in his club.

Miguel's club has more possible team combinations because he has more members on each team than Brent does.

Question

Angelique Higgins

Mathematics

9 December, 18:31

Brent's after-school game club has 12 members from which a six-member team is created. Miguel's after-school sports club has 10 members from which a six-member team is created.

Which student's club has more possible combinations for his six-member team?

Brent's club has more possible team combinations because he has fewer members on each team than Miguel's does.

Brent's club has more possible team combinations because there are more members to choose from.

Miguel's club has more possible team combinations because there are fewer members in his club.

Miguel's club has more possible team combinations because he has more members on each team than Brent does.

+1

Answers (1)

Know the Answer?

Briana Blanchard · Answer 1

From the given above, solving for the combination of six-member team from Bret's after-school game club will give us,

12C6 = 924

That from Miguel's after-school game club will give us,

10C6 = 210

Obviously, Bret's club will have more number of possible combinations because there are more members to choose from. The answer is the second choice.