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23 August, 06:13

What is the sum of the arithmetic sequence 3,9,15, if there are 36 terms ... ?

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  1. 23 August, 06:23
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    n = 36

    a = 3

    d = 3

    (n/2) (2a + (n - 1) d)

    (36/2) (2 (3) + (36 - 1) 3)

    18 (6+35 (3))

    18 x 111 = 1998

    The sum is 1998
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