Ask Question
26 April, 04:50

A classroom contains 13 students. A student committee of 3 (president, vice-president, and treasurer) must be selected. Harry Potter will serve only as president and only if either of his friends Ron Weasley or Hermione Granger serve as vice president; otherwise he leaves the group. The others (including Ron and Hermione) have no such restrictions. What is the probability that Ron or Hermione become the president of this group

+1
Answers (1)
  1. 26 April, 05:14
    0
    16.39%

    Step-by-step explanation:

    We have a total number of forms, which are as follows:

    -Harry Potter will serve as President AND Ron will serve as Vice President AND anyone will serve as Treasurer:

    p1 = 1P11 = 11! / (11-1) ! = 11

    -Harry Potter will serve as President AND Hermione will serve as Vice President AND anyone who serves as Treasurer is:

    p2 = 1P11 = 11! / (11-1) ! = 11

    - Harry Potter will not serve as President means that no one except Harry Potter (12 remaining students) serve in three locations:

    p3 = 12P3 = 12! / (12-3) ! = 1320

    in total it would be:

    11 + 11 + 1320 = 1342

    Now the favorable cases are:

    - Hermione becomes the president of this group, which means that anyone except Hermione and Harry Potter (11 remaining students) serve in the remaining two places:

    p1 = 11P2 = 11! / (11-2) ! = 110

    - Ron becoming the president of this group means that anyone except Ron and Harry Potter (remaining 8 students) serve in the remaining two places:

    p2 = 11P2 = 11! / (11-2) ! = 110

    adding it would be: 110 + 110 = 220

    now then the final probability is the favorable cases among the totals:

    220/1342 = 0.1639

    Which means that the probability is 16.39%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A classroom contains 13 students. A student committee of 3 (president, vice-president, and treasurer) must be selected. Harry Potter will ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers