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15 July, 06:07

What's the reasoning for if a = b, and c > 0, then a+c > b?

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  1. 15 July, 06:34
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    If a = b, and c > 0, proved.

    Step-by-step explanation:

    Given by question,

    a = b and c > 0

    ∵ a + c > b

    Put a = b, we get

    ⇒ a + c > b

    ⇒ b + c > b

    ⇒ c > b - b

    ⇒ c > 0, proved.

    Thus, if a = b, and c > 0, proved.
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