What's the reasoning for if a = b, and c > 0, then a+c > b?

If a = b, and c > 0, proved.

Step-by-step explanation:

Given by question,

a = b and c > 0

∵ a + c > b

Put a = b, we get

⇒ a + c > b

⇒ b + c > b

⇒ c > b - b

⇒ c > 0, proved.

Thus, if a = b, and c > 0, proved.