A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard, which is 40 feet by 65 feet. If a neighbor's yard is 50 feet by 80 feet, what would the neighbor be charged based on how much Mr. Jones was charged?

Question

Alannah Solomon

Mathematics

4 November, 07:55

A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard, which is 40 feet by 65 feet. If a neighbor's yard is 50 feet by 80 feet, what would the neighbor be charged based on how much Mr. Jones was charged?

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Abril Holloway · Answer 1

Answer: The neighbor would be charged $80

Step-by-step explanation:

The dimensions of Mr Jones's yard are 40 feet by 65 feet. This means that the shape of Mr Jones's yard is rectangular. The formula for determining the area of a rectangle is length * width. The area of the yard would be

40 * 65 = 2600 square feet

Mr. Jones was charged $52 for his yard. This means that the amount that he was charged per square foot would be 52/2600 = $0.02

If a neighbor's yard is 50 feet by 80 feet, it means that the area of his yard would be 50 * 80 = 4000 square feet. The amount that the neighbor would be charged is

4000 * 0.02 = $80