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15 February, 09:57

What are the zeros of the function?

f (x) = 2x3+6x2-8x

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  1. 15 February, 10:05
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    x = 0, 4, - 1.

    Step-by-step explanation:

    2x3 + 6x2 - 8x = 0 Take out the common factor 2x:

    2x (x^2 - 3x - 4) = 0

    2x (x - 4) (x + 1) = 0

    2x = 0 or x - 4 = 0 or x + 1 = 0, so:

    x = 0, 4, - 1.
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