Tony will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $60 and costs an additional $0.30 per mile driven. The second plan has no initial fee but costs $0.80 per mile driven. How many miles would Tony need to drive for the two plans to cost the same?

Question

Giovanna

Mathematics

13 March, 06:28

Tony will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $60 and costs an additional $0.30 per mile driven. The second plan has no initial fee but costs $0.80 per mile driven. How many miles would Tony need to drive for the two plans to cost the same?

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Jerimiah Foley · Answer 1

Hello.

The first car has a cost that can be calculated as a function of the miles driven:

f (m) = 60 + 0.3m

The second has a similar comportment:

s (m) = 0.8m

We want f (m) = s (m).

60 + 0.3m = 0.8m

0.8m - 0.3m = 60

0.5m = 60

m = 60 / 0.5

m = 120.

Tony would need to drive 120 miles to pay the same amount.