How do you write y=-4x^2-16x-14 in vertex form?

Question

Pedro Harding

Mathematics

29 August, 10:13

How do you write y=-4x^2-16x-14 in vertex form?

+5

Answers (2)

Know the Answer?

Arjun Lane · Answer 1

y = - 4 (x + 2) ² + 2

Corinne Walters · Answer 2

y = - 4x² - 16x - 14

Take the coefficient of x² as the common factor

y = - 4 (x² + 4x + 7/2)

Add (b/2) ² to complete the square

y = - 4 (x² + 4x + 2² - 2² + 7/2)

Complete the square

y = - 4 ((x + 2) ² - 1/2)

Remove the bracket

y = - 4 (x + 2) ² + 2

Answer: y = - 4 (x + 2) ² + 2