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10 November, 07:36

A sprinkler rotates through an angle of 115° spraying water outward for a distance of 12 ft. find the exact area watered, then round the result to the nearest tenth of a square foot.

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  1. 10 November, 07:52
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    The sprinkler rotates through an angle of 115° and sprinkles water outward for a distance of 12 ft.

    Therefore the radius of the circular section is 12 ft as shown in the diagram below.

    The total circle occupies 360°. Therefore the area watered is

    A = (115/360) * π * (12 ft) ²

    = 144.513 ft²

    Answer: 144.5 ft (nearest tenth)
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