Solve for x, x^2-3x-5=0

Okay so for this one, we have to isolate our X. Lets start by moving the negative 5 on the other side of the equal sign. Remember to not mix a number that is with an X with a normal number (in this case it would be the - 3x and the - 5). So in putting our - 5 on the other sign it becomes positive. Here's what we have: x^2-3x=5. x^2 is the same thing as 2x. So now you have to minus 3x off of your 2x. This gives us - 1x, but can just be put as - x. So now we have - x=5. You're answer could either be 5 or - 5 if you decided to divide it by - 1 seeing as your - x is technically - 1.