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20 October, 18:43

Assume that z scores are normally distributed with a mean of 0 and a standard deviation of 1. if p (z >

c. = 0.1093, find

c.

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  1. 20 October, 18:44
    0
    Given that μ=0, and σ=1, P (z>c) = 0.1093

    thus

    P (z
    hence the value of c will be:

    z-score = (c-μ) / σ

    thus

    1.23 = (c-0) / 1

    c=1.23
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