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28 June, 03:31

Sec[sin-1 square root of 3 over 2]

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  1. 28 June, 03:32
    0
    Answer: √3/2

    Step-by-step explanation:

    Sin[sin⁻¹ (√3/2) ]

    sin⁻¹ (√3/2 = 60°

    60° is the acute angle, in the first quadrant

    Therefore;

    Sin[sin⁻¹ (√3/2) ] = sin 60°; since sin⁻¹ (√3/2 = 60°

    Sin 60° = √3/2

    Therefore, the answer = √3/2
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