R (x) = x-3

s (x) = 4x²

write the expressions for (s+r) (x) and (s-r (x) and evaluate (s. r) (2)

What we are given:

r (x) = x - 3

s (x) = 4x²

We have to find:

(s + r) (x) = (x - 3 + 4x²)

→ 4x² + x - 3

(s - r) (x) = (x - 3 - 4x²)

→ - 4x² + x - 3

For the last function, I am confused whether it is a multiplication or composite function, so I am going to do both.

Multiplication:

(x - 3 (4x²)) (2)

(4x³ - 12x²) (2)

4 (2) ³ - 12 (2) ²

4 (8) - 12 (4)

32 - 48

→ - 4

Composite function:

r (s (x)) (2) = r (4x²) = 4x² - 3 = 4 (2) ² - 3 = 4 (4) - 3 = 16 - 3

→13