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29 July, 18:30

A rectangular room is 5 meters longer than it is wide and it's perimeter is 34 meters fin the dimension of the room

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Answers (2)
  1. 29 July, 18:47
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    Step-by-step explanation:

    P = 2 (L + W)

    P = 34

    L = W + 5

    34 = 2 (W + 5 + W)

    34 = 2 (2W + 5)

    34 = 4W + 10

    34 - 10 = 4W

    24 = 4W

    24/4 = W

    6 = W <== = 6 meters wide

    L = W + 5

    L = 6 + 5

    L = 11 <== = 11 meters long
  2. 29 July, 18:57
    0
    Step-by-step explanation:

    The length and width is unknown. What we do know is that the length is 5m longer than the width. Knowing this we can make the w = x, and the l = x + 5. This is, again, because the width is unknown and the length is the width + 5. Perimeter is 2 (l + w) (p = 2 (l + w)). We know the perimeter is equal to 34. Our equation would be 34 = 2 (l + w). Substituting the length and width for the new variables we created: 34 = 2 (x + (x + 5)). Simplified a bit this would be 34 = 2 (x + x + 5) or 34 = 2 (2x + 5) Now solve for x. x will be equal to your width and x + 5 will be equal to your l
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