A baker bakes a batch of muffins and splits the batch evenly into six different trays. She then adds five croissants to each tray. If each tray now contains at least twenty baked goods, what is the least possible number of muffins in the baker's original batch

Original batch had 90 muffins

Step-by-step explanation:

m = muffins in original batch

So, each tray has m/6 muffins and 5 croissants, which totals m/6+5. The value must be at least 20, so we have this inequality:

m/6+5 is greater than or equal to 20. We multiple each side by 6 and get:

m is greater than or equal to 90 muffins.