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13 March, 20:46

The 12th term and the sim of 1+3+5+7 + ...

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  1. 13 March, 21:08
    0
    To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.

    subtract 1 from 3

    3-1=2

    So each number is having 2 added to it.

    Now add two to 7 and the numbers afterwards till you get the 12th term

    7+2=9

    1+3+5+7+9

    9+2=11

    1+3+5+7+9+11

    11+2=13

    1+3+5+7+9+11+13

    13+2=15

    1+3+5+7+9+11+13+15

    15+2=17

    1+3+5+7+9+11+13+15+17

    17+2=19

    1+3+5+7+9+11+13+15+17+19

    19+2=21

    1+3+5+7+9+11+13+15+17+19+21

    21+2=23

    1+3+5+7+9+11+13+15+17+19+21+23

    So 23 is the 12th term
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