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15 September, 03:31

Which polynomial function f (x) has a leading coefficient of 1, root - 4, 2, and 9 with multiplicity 1, and root - 5 with multiplicity 3?

A. f (x) = 3 (x+5) (x+4) (x-2) (x-9)

B. f (x) = 3 (x-5) (x-4) (x+2) (x+9)

C. f (x) = (x+5) (x+5) (x+4) (x-2) (x-9)

D. f (x) = (x-5) (x-5) (x-4) (x+2) (x+9)

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  1. 15 September, 03:38
    0
    So, here, take each root and create a factor that uses the opposite of the root number.

    (x+4) (x-2) (x-9) (x+5) ... but the x+5 factor is a mult. 3 so it is taken to the third power. So the answer is not one of the options. The answer should be (x+4) (x-2) (x-9) (x+5) (x+5) (x+5) = f (x)
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