Find the probability that when 200 reservations are accepted for united flight 15, there are more passengers than seats available

The solution for this problem is:

We know the problem has the following given:

Sample size of 200

X = 182

And the probability of. 9005; computation: 1 -.0995 =.9005

So in order to get the probability:

P (x > = 182) = 1 - 0.707134 =.292866 is the probability that when 200 reservations

are recognized, there are more passengers showing up than there

are seats vacant.

The other solution is:

p (> = 182) = p (183) + P (184) + P (185) + ... + P (199) + P (200) = 0.292866