A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger?

2/27

Step-by-step explanation:

In the question we have:

4 snickers

2 packages of M&M's

3 Butterfingers.

Total number of candies in the Halloween bag = 9

Probability of selecting some M&M's and putting them back = 2/9

Probability of selecting a Butter finger = 3/9

Therefore, the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger =

Probability of selecting some M&M's and putting them back * Probability of selecting a Butter finger

2/9 * 3/9

= 6 / 81

= 2/27