If f (x) = 2x^2+8, what is the positive value of x for which f (x) = 136

Question

Kelton Whitehead

Mathematics

15 December, 01:08

If f (x) = 2x^2+8, what is the positive value of x for which f (x) = 136

+1

Answers (2)

Know the Answer?

Eric Rich · Answer 1

I would say the answer is 8:

f (x) = 2x^2 + 8

f (x) = 136

f (x) = f (x)

2x^2 + 8 = 136

Subtract both sides by 8

2x^2=128

Divide both sides by 2

x^2 = 64

Square both sides

x = 8

Luciana Ruiz · Answer 2

136 = 2x^2 + 8

128 = 2x^2

64 = x^2

8 = x