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15 December, 01:08

If f (x) = 2x^2+8, what is the positive value of x for which f (x) = 136

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Answers (2)
  1. 15 December, 01:17
    0
    I would say the answer is 8:

    f (x) = 2x^2 + 8

    f (x) = 136

    f (x) = f (x)

    2x^2 + 8 = 136

    Subtract both sides by 8

    2x^2=128

    Divide both sides by 2

    x^2 = 64

    Square both sides

    x = 8
  2. 15 December, 01:29
    0
    136 = 2x^2 + 8

    128 = 2x^2

    64 = x^2

    8 = x
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