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26 November, 21:15

Circle the GCF of 28x3 and

16x2y2

28x3: 2.2.7.*•*•*

16x2y2:2.2.2.2. x. x. y. y

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Answers (1)
  1. 26 November, 21:34
    0
    Step-by-step explanation:

    28x^3 = 2 * 2 * 7 * x * x * x

    16x^2Y^2 = 2 * 2 * 2 * 2 * x * x * y * y

    GCF = 2 * 2 * x * x = 4x^2

    Circle which are in both
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